Electric Potential Energy Question - Distance Between Charges and Ratio?

AI Thread Summary
The discussion revolves around a physics problem involving two charges, +q1 and -q2, where the total electric potential is zero at two specific points. Participants express confusion about how to apply the relevant equations, particularly V = kq/r, to determine the distance between the charges and the ratio of their magnitudes. Key hints suggest focusing on the algebraic sum of potentials from both charges and eliminating constants due to the zero potential condition. The book answer indicates that the ratio q1/q2 is 3.67, but participants seek clarification on the solution process. Overall, the thread highlights the challenges of applying theoretical concepts to practical problems in electric potential energy.
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Homework Statement



A positive charge +q1 is located to the left of a negative charge -q2. On a line passing through the two charges, there are two places where the total potential is zero. The first place is between the charges and is 4.00 cm to the left of the negative charge. The second place is 7.00 cm to the right of the negative charge. (a) What is the distance between the charges? (b) Find q1/q2, the ratio of the magnitudes of the charges.

Homework Equations



Not sure which one to use. the EPE one or kq1/x = kq2/d-x

The Attempt at a Solution



Ok...This might be one of the most confusing questions I've ever encountered in Physics! I drew a diagram, but i had no clue what i was doing. I know the equation V = Kq/r is supposed to be used, but i don't know what to substitute in the problem! please show me how you do this problem. appreciate all the help i can get! WHAT IS Q1 AND Q2? my main problem

Book Answer: I only have part b, which is 3.67
 
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The only equation you need is

V = k \frac{q}{r}

Some hints to solve the problem:
1. The total potential is the algebraic sum of the potentials as a result of the two charges.
2. A negative charge produces a negative potential while a positive charge results in a positive potential at a point (a positive test charge need to be pushed up against a positive charge).
3. You can eliminate k from the equations due to the fact that the sum is zero in both cases.
4. You can insert the distances in centimeters in the equations since the conversion factor, \times 10^{-2}, can be eliminated due to the fact that sum is zero.
5. Compare the ratios of the charges!
 
hey uhh can u tell me how u found the answer to part b?
 
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