Electricity: voltage calculation in serial

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Homework Help Overview

The discussion revolves around calculating the voltage U in a circuit with resistors connected in series, given a voltmeter reading of 80V. Participants are exploring the relationships between voltage, current, and resistance in this context.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formulation of equations based on the given voltmeter reading and question the role of the variable 'R'. There is an exploration of how to derive a second equation to create a system of linear equations. Some participants attempt to express the total voltage in terms of the current and resistances.

Discussion Status

Several participants have provided insights and attempted to clarify the relationships between the variables involved. There is an ongoing exploration of the equations needed to solve for U, with some guidance offered on how to approach the problem. However, no explicit consensus has been reached regarding the final solution.

Contextual Notes

Participants are working under the constraints of the problem statement and the information provided by the voltmeter. There is a noted ambiguity regarding the interpretation of the variable 'R' and its implications for the calculations.

Epoch
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Homework Statement


Calculate the voltage U.
The voltmeter gives a value of 80V.
exercise.png


The Attempt at a Solution


[/B]
3RI + 4RI - U = -80
How can I create a System of Linear equations if I have only one equation?
Do I miss something?

My answer sheet says U = 150V.
 
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What is 'R'? Is it a variable, or does it represent "resistor"? I guess it really doesn't matter. If it is a variable, the R's should cancel out. You know that the voltage across the 2 inside resistors is 80 V, so you should be able to come up with a second equation for that.
 
Epoch said:

Homework Statement


Calculate the voltage U.
The voltmeter gives a value of 80V.
View attachment 194684

The Attempt at a Solution


[/B]
3RI + 4RI - U = -80
How can I create a System of Linear equations if I have only one equation?
Do I miss something?

My answer sheet says U = 150V.

Let I be the current through the circuit. The V to the drop at 2R and 6R, so
2RI + 6RI = 80
8RI = 80
RI = 10

For the whole circuit,
U - 3RI - 2RI - 6RI - 4RI = 0

Try to take it from there!
 
D Nguyen said:
Let I be the current through the circuit. The V to the drop at 2R and 6R, so
2RI + 6RI = 80
8RI = 80
RI = 10

For the whole circuit,
U - 3RI - 2RI - 6RI - 4RI = 0

Try to take it from there!

Thanks, I got it.
 
D Nguyen said:
Let I be the current through the circuit. The V to the drop at 2R and 6R, so
2RI + 6RI = 80
8RI = 80
RI = 10

For the whole circuit,
U - 3RI - 2RI - 6RI - 4RI = 0

Try to take it from there!

RI = 10
U - 3RI - 2RI - 6RI - 4RI = 0
U - 3*10 - 2*10 - 6*10 - 4*10 = 0
U - 30 - 20 - 60 - 40 = 0
U - 150 =0
U = 150V

I found it, thanks for your help.
 

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