Electricity: voltage calculation in serial

AI Thread Summary
The discussion revolves around calculating the voltage U in a circuit where a voltmeter reads 80V. The initial equation presented is 3RI + 4RI - U = -80, leading to confusion about creating a system of linear equations. Participants clarify that the current I can be used to derive additional equations, specifically noting that 2RI + 6RI = 80 simplifies to RI = 10. Ultimately, through substitution and solving, it is confirmed that U equals 150V. The conversation highlights the importance of understanding circuit relationships and using known values to solve for unknowns.
Epoch
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Homework Statement


Calculate the voltage U.
The voltmeter gives a value of 80V.
exercise.png


The Attempt at a Solution


[/B]
3RI + 4RI - U = -80
How can I create a System of Linear equations if I have only one equation?
Do I miss something?

My answer sheet says U = 150V.
 
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What is 'R'? Is it a variable, or does it represent "resistor"? I guess it really doesn't matter. If it is a variable, the R's should cancel out. You know that the voltage across the 2 inside resistors is 80 V, so you should be able to come up with a second equation for that.
 
Epoch said:

Homework Statement


Calculate the voltage U.
The voltmeter gives a value of 80V.
View attachment 194684

The Attempt at a Solution


[/B]
3RI + 4RI - U = -80
How can I create a System of Linear equations if I have only one equation?
Do I miss something?

My answer sheet says U = 150V.

Let I be the current through the circuit. The V to the drop at 2R and 6R, so
2RI + 6RI = 80
8RI = 80
RI = 10

For the whole circuit,
U - 3RI - 2RI - 6RI - 4RI = 0

Try to take it from there!
 
D Nguyen said:
Let I be the current through the circuit. The V to the drop at 2R and 6R, so
2RI + 6RI = 80
8RI = 80
RI = 10

For the whole circuit,
U - 3RI - 2RI - 6RI - 4RI = 0

Try to take it from there!

Thanks, I got it.
 
D Nguyen said:
Let I be the current through the circuit. The V to the drop at 2R and 6R, so
2RI + 6RI = 80
8RI = 80
RI = 10

For the whole circuit,
U - 3RI - 2RI - 6RI - 4RI = 0

Try to take it from there!

RI = 10
U - 3RI - 2RI - 6RI - 4RI = 0
U - 3*10 - 2*10 - 6*10 - 4*10 = 0
U - 30 - 20 - 60 - 40 = 0
U - 150 =0
U = 150V

I found it, thanks for your help.
 
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