Electron accelerated through field

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The discussion revolves around calculating the wavelength of an electron beam accelerated through a potential field, achieving a velocity of 5.45x10^7 m/s. Participants suggest using the relationship between mass, velocity, and wavelength, referencing equations like mc^2=hf and the Lorentz transformation for energy. One contributor calculates the wavelength to be approximately 0.0013 nanometers. The conversation emphasizes the importance of understanding the relationship between kinetic energy and wavelength in quantum mechanics. Ultimately, the focus is on applying the correct formulas to derive the wavelength of the electron beam.
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A beam of electrons is accelerated through a field of a different potential which produces a velocity of 5,45x10^7 m/s. The mass of an electron being 9,11x10^(-31) kg, what would be the wave length of the electron beam?

A question i encountered when doing homework, i need some help with this one..anyone? thanks:redface:
 
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So you need some relation between the mass, velocity and wavelength of your electrons. Did you learn about anything that relates these?
 
would it be...
mc^2=hf
(5.45x10^7)(3x10^8)^2=(6.626x10^-34)(f)...find the frequency and therefore the wave length?...id like to know wether i should be finding the electron's rest energy, kinetic energy..or should i use (mc^2)/(1-v^2/c^2)^1/2?..(lorentz transformation of energy)
 
i got 0,0013 nanometers
 
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