Electron acceleration and kinetic energy

AI Thread Summary
An electron accelerated through a potential difference of 10 kV gains kinetic energy. The calculation in Joules yields 1.6 x 10^-15 J. To convert this to electron volts (eV), the conversion factor of 1 eV = 1.6 x 10^-19 J is used. The resulting kinetic energy is correctly expressed as 10,000 eV or 10 keV. This confirms the relationship between potential difference and kinetic energy in electron volts.
wakejosh
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Homework Statement



an electron in a TV picture tube is accelerated through a potential difference of 10 Kv before it hits the screen. What is the kinetic energy of the electron in electron volts when it hits the screen?



ok, so i know how to work this for Joules and i get: 1.6 x 10 ^-15 J. Now i am not so sure about converting this to eV, I looked up a conversion on the internet and found: 1 eV= 1.6 x 10^-19 J so is it correct to say that the answer is:

1.0 x 10 ^4 eV

any help is appreciated.
 
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Yep. You can also write it as 10 KeV.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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