Electrostatic and gravitational forces

AI Thread Summary
To determine the distance between a single proton and a group of 13 protons where the electrostatic force equals the gravitational force on a proton, the relevant formulas involve the mass of a proton and its charge. The mass of a proton is 1.67 x 10^-27 kg, and its charge is 1.6 x 10^-19 C. The electrostatic force can be calculated using Coulomb's law, while the gravitational force can be derived from the mass and gravitational acceleration. The user attempted to calculate the distance using the formula but expressed confusion about incorporating the group of 13 protons. Ultimately, the calculated distance of 43.7 centimeters was questioned for accuracy.
Rowie25
Messages
15
Reaction score
0

Homework Statement


How far (in cm) apart must be proton from group of 13 protons if the magnitude of the electrostatic force acting on either one due to the others is equal to the magnitude of the gravitational force on a proton at Earth's surface?


So, I know that the mass of a proton is 1.67*10^-27 kg and that the charge on the proton is 1.6*10^-19 C. I am using the formula: 1/(4piEo) times (q1q2 divided by r^2) equals mg. So I thought you could set it up like this: (1.6*10^-19 times (13)(1.6*10^-19) divided by (1.6*10^-27)(9.8). That multiply that quotient by r^2=9*10^9. I don't think I did it right, I'm confused at what to do with the 13. Thanks!
 
Physics news on Phys.org
I got something like .437 meters and changed that into 43.7 centimeters. Does that seem right?
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

[Magnetism] Determine the direction of the force experienced by a (+)C
Replies
2
Views
1K
What Was the Initial Speed of the Proton in a Collision?
Replies
2
Views
3K
Solve Proton Homework: Min Speed to Miss Lower Plate
Replies
2
Views
8K
EPE and particle collision (grade 12)
Replies
7
Views
2K
Electric Field Force Exerted Vertically
Replies
9
Views
8K
Electrostatic Potential / Work Question?
Replies
3
Views
9K
Physics 12 Electric Energy Question
Replies
13
Views
2K
Length contraction numerical problem
Replies
1
Views
1K
Magnitude of electric force on a proton
Replies
6
Views
10K
Cyclotron Radius of Proton: .625m
Replies
3
Views
2K

Hot Threads

Recent Insights

Back
Top