Electrostatic charge between a na+ ion and a cl- ion

AI Thread Summary
The discussion centers on calculating the electrostatic charge between Na+ and Cl- ions. Na+ carries a positive charge equivalent to one elementary charge, while Cl- has a negative charge of one elementary charge due to an extra electron. The user is struggling with discrepancies in their calculations, finding results that differ by a factor of ten. There is an offer for assistance in checking the calculations to resolve the issue. Accurate charge values are essential for correct electrostatic force calculations.
flamewolf393
Messages
2
Reaction score
0
I have the relevant equation, I just need to know the charges (in coloumbs) of the two ions so I can plug them into it. I thought that it would just be the equivalent charge of the one spare proton/electron, but that did not work so I guess it was a faulty assumption. I have not been able to find this information anywhere.
 
Physics news on Phys.org
Cl- means one extra negative elementary (electron) charge. Na+ is one extra positive elementary charge.
 
Thats what I thought, but when I plug the values for those into the equation, it comes out with an answer that is off by a factor of 10 decimal places.
 
Do you want me to check your calc?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top