Electrostatics and infinately charged plate question driving me nuts

AI Thread Summary
An electron released from rest 2.0 cm from an infinite charged plane accelerates toward it, colliding at a speed of 1.0x10^7 m/s. The surface charge density of the plane is calculated to be 2.52×10−7 C/m^2. Participants in the discussion emphasize the importance of using kinematic equations to relate velocity, distance, and acceleration. The correct approach involves using the average velocity and applying relevant equations for accelerated motion. The conversation highlights the significance of understanding the distinction between constant and accelerated motion in solving the problem.
ursulan
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Homework Statement


An electron is released from rest 2.0 cm from an infinite charged plane. It accelerates toward the plane and collides with a speed of 1.0x10^7m/s. What is the surface charge density of the plane?The answer is 2.52×10−7 C/m^2 !


Homework Equations


v=d/t, d=0.5at^2, E=n/2*8.85x10^-12, F=ma=Eq


The Attempt at a Solution


I don't know what to do with the velocity. I tried relating it to energy but got stuck.
 
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ursulan said:
I don't know what to do with the velocity.
Use that and the distance to find the electron's acceleration.
 
using v=d/t t is 2E-9
using a=v/t a is 5E15
E=ma/q E=28469
E=n/(2 epsilon not).. n=5.03E-7

which is 2 times too big, but isn't E=n/(2 epsilon not) the correct equation, with the 2?
 
ursulan said:
using v=d/t t is 2E-9
That equation applies for constant velocity, not accelerated motion. But you can use it if you replace v (the final velocity) with the average velocity. What's the average velocity?

You can also make use of additional kinematic relationships.
 
ahh so I guess you mean Vf^2=V0^2 + 2ad because that works haha

Thanks!
 
That's the one. :wink:
 
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