What Is the Speed of a Proton Between Two Plates with a 60V Difference?

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A proton accelerates from rest between two plates with a 60V potential difference, and the goal is to determine its speed upon reaching the second plate. The relevant equations include the relationship between voltage, electric field, and kinetic energy. The initial calculations involved incorrect mass for the proton, mistakenly using the mass of an electron instead. Once the correct mass was applied, the problem was resolved. Accurate unit representation is crucial for clarity in such calculations.
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1. The problem statement, all variables and 'given'/'known' data
A proton accelerates from rest from plate X to plate Y. If the potential difference between the 2 plates is 60.0V, what is the speed of the proton when it reaches plate Y?

2. Governing equations
V = E/q
Ekf - 1/2mv^2

The Attempt at a Solution


E = (60V)(1.6x10^-19C)
E = 9.6x10^-18 V/m

Ekf = 1/2mv^2
9.6E-18 J = 1/2(9.11x10^-31kg)v^2EDIT: added units

And when I solve for v my answer is not correct. So I'm making a mistake somewhere.

Thanks
 
Last edited:
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Good job posting the question. I'm having trouble checking your work because units are not shown throughout. Could you please include units on things like the 1.6x10^-19 term, etc.? Thanks.
 
added units
thanks
 
The mass of a proton is not 9.11e-31 Kg!
 
Oh dear, how could I mix that up.

I did it as an electron...

Problem solved, thanks
 

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