How to Find the Angle of a Child on a Swing at Maximum Height

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To find the angle of a child on a swing at maximum height, the scenario involves a swing with ropes of length 2.5 m and a velocity of 0.7 m/s at the lowest point. The relevant equation derived from energy conservation is 1/2Vi^2 = gh, which allows for the calculation of maximum height, determined to be 0.025 m. The discussion suggests using a free-body diagram to further analyze the forces at play and determine the angle between the ropes and the vertical. Additional guidance is requested to proceed with the solution.
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1. Child on a Swing
This child involves a child swinging on a swing supported by ropes of length 2.5 m. The child's velocity at the bottom of his arc is given as .7 m/s. The goal of the problem is to find the angle between the ropes and the vertical when the child is at his maximum height.


Homework Equations


1/2mVi^2 = mgh
divide through by m ---> 1/2Vi^2 = gh


The Attempt at a Solution


In solving this problem, I was able to find the child's maximum height using the above equation. This I found to be .025 m, however, beyond this point I am at a loss for what to do.

Any help would be greatly appreciated!
 
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try to draw a free-body diagram .. and go on from there ..
 
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