Calculating Energy Released by Fission of 1g of U-235

[kingstar]

Homework Statement

Estimate the energy released, in Joules, by the fission of 1g of U-235 according to the equation:


$^{235}_{92}{U}$ + $^{1}_{0}{n}$ → $^{144}_{56}{Ba}$ + $^{90}_{36}{Kr}$ + 2$^{1}_{0}{n}$ + Q

atomic masses:

$^{235}_{92}{U}$ = 235.04438u

$^{144}_{56}{Ba}$ = 143.92279u

$^{90}_{36}{Kr}$ = 89.92089u

$^{1}_{0}{n}$ = 1.00866u

Avogadro's number = 6.023 x 10²³
1u = 931MeV
1MeV = 1.6 x 10^-13J

Homework Equations

The Attempt at a Solution

(235.04438u + 1.00866u) - (143.92279u + 89.92089u + 1.00866u + 1.00866u) = 0.19204u

0.19204u x 931 = 178.78924MeV
178.78924 x 1.6 x 10^-13J = 2.86 x 10^-11

Do I then do (6.023 x 10²³/235) x 2.86 x 10^-11 = 7.33 x 10¹⁰J

For the final answer?

Thanks

 

[barryj]

Looks good to me.

 

[kingstar]

Looks good to me.

Thanks.