Entropy Calculation in Thermodynamics Homework

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SUMMARY

The discussion focuses on calculating the variation of entropy for two thermodynamic processes involving water. For process (a), the correct formula is ΔS = Cp * ln(T_final/T_initial), where Cp is 4.18 kJ/kg·K, and the temperatures are 313.15 K and 288.15 K. For process (b), the user incorrectly applies the ideal gas equation ΔS = R ln(P1/P2), which is not suitable for liquids; instead, the change in entropy must consider the work done during compression from 1 atm to 7 atm at 15ºC.

PREREQUISITES
  • Understanding of thermodynamic principles, specifically entropy calculations.
  • Familiarity with the specific heat capacity of water (Cp = 4.18 kJ/kg·K).
  • Knowledge of the ideal gas law and its limitations regarding phase changes.
  • Basic concepts of pressure and temperature in thermodynamic processes.
NEXT STEPS
  • Study the derivation and application of the entropy formula ΔS = Cp * ln(T_final/T_initial) for liquids.
  • Learn about the work done during isothermal compression of liquids.
  • Research the differences between ideal gas behavior and real liquid behavior in thermodynamics.
  • Explore the implications of phase changes on entropy calculations in thermodynamic systems.
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Students and professionals in thermodynamics, particularly those studying or working with heat transfer and entropy calculations in liquid systems.

ruiwp13
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Homework Statement


Calculate the variation of entropy in the following processes:
a) Heating of 18 kg of water from 15 to 40ºC at ambient pressure.
b) Compression of 9 kg of water from ambient pressure to 7atm at the temperature of 15ºC.


Homework Equations


ΔS=Cp*ln(T_final/T_initial)

The Attempt at a Solution




So for a) I checked the Cp of water getting 4.18KJ/kgºK and multiplied it by the 18 kg. Then I tried to apply the formula with the Cp and the Tfinal=313.15K and TInitial=288.15K and I think it is correct.

For b) I think I have to use ΔS=R ln (P1 / P2) but I'm not sure. And if it is that expression, the Pressure must be in kPa?
 
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ruiwp13 said:

Homework Statement


Calculate the variation of entropy in the following processes:
a) Heating of 18 kg of water from 15 to 40ºC at ambient pressure.
b) Compression of 9 kg of water from ambient pressure to 7atm at the temperature of 15ºC.


Homework Equations


ΔS=Cp*ln(T_final/T_initial)

The Attempt at a Solution




So for a) I checked the Cp of water getting 4.18KJ/kgºK and multiplied it by the 18 kg. Then I tried to apply the formula with the Cp and the Tfinal=313.15K and TInitial=288.15K and I think it is correct.

For b) I think I have to use ΔS=R ln (P1 / P2) but I'm not sure. And if it is that expression, the Pressure must be in kPa?

In part (a) the equation you used applies to liquid water or to an ideal gas at constant volume. I assume you knew you were doing it for liquid water. The equation you used in part (b) is for an ideal gas, but not a liquid. The question must be referring to liquid water, because water can't exist as a vapor at these pressures and 15C. If the temperature doesn't change, what is the change in the internal energy of the liquid water? How much work is done on the water to compress it from 1 atm to 7 atm? How much heat is involved? What is the change in entropy?


Chet
 
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