Equation for Fourth Force and its Line of Action?

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The discussion centers on calculating the fourth force (F4) required for equilibrium in a system with three given forces. The calculated F4 is confirmed as -21i + 21j, aligning with the initial findings. However, there is confusion regarding the vector equation of its line of action, with the poster initially deriving r=-(8/21)i+k(-i+j) but later realizing a typo in their calculations. The correct interpretation of the problem is clarified, emphasizing that F4 is an additional force for equilibrium rather than a replacement. The poster ultimately acknowledges the correct book answer as 92/21, resolving their confusion.
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Homework Statement
Find the equivalent force
Relevant Equations
Balance of moments
Could anyone please help with the following?

Three forces of magnitudes 10, 3 * sqrt(5) and 25 Newtons act along lines whose vector equations are respectively:

r1 = i - 2j + k(4i + 3j) , r2 = -2i + 4j + k(2i - j) and r3 = 4i + k(7i - 24j)

A fourth force F4 is introduced which reduces the system to equilibrium.

Find F4 and the vector equation of its line of action:

I get the same answer as the book for the first part, F4 = -21i + 21j but not for the second part.

I take moments about -2i + 4j to find the y-intercept of the line of action and I am led to the equation r=-(8/21)i+k(-i+j) but the book answer is r=(22/21)i + k(-i+j).

Can anyone help confirm if it is the book or I (as I suspect) that is worng?

Thanks,
Mitch.
 
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gnits said:
I take moments about -2i + 4j to find the y-intercept of the line of action and I am led to the equation r=-(8/21)i+k(-i+j) but the book answer is r=(22/21)i + k(-i+j).
I get 92/21.
Please post your working.
 
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We know from the first part that:

F1 = 8i + 6j
F2 = 6i-3j
F3 = 7i-24j

Resolving horizontally and vertically gives us F4 = -21i+21j

Taking anti-clockwise moments about (-2,4) gives:

8*6 + 6*3 + 7*4 - 21 * 6 = 21 * (y' - 4) + 21 * 2

This leads to y' = -8/21 and so to an equation of y = -x - 8/21 and so when y = 0 then x = -8/21 hence my answer of r=-(8/21)i+k(-i+j)

Thanks,
Mitch.
 
gnits said:
8*6 + 6*3 + 7*4 - 21 * 6 = 21 * (y' - 4) + 21 * 2
THere's a typo, but probably just in making the post. I think you meant
8*6 + 6*3 + 7*4 - 24 * 6 = 21 * (y' - 4) + 21 * 2
But shouldn’t it be
8*6 + 6*3 + 7*4 - 24 * 6 + 21 * (y' - 4) + 21 * 2 = 0
?
That would match my answer.
 
Thanks so much (yes it was a typo in posting). I misread the question as saying that the forces were replaced by F4 which was to be equilvalent to the initial forces, but of course that's not what it is asking, it is saying that F4 is added into the system to create equilibrium.

Thanks again,
Mitch.
 
gnits said:
Thanks so much (yes it was a typo in posting). I misread the question as saying that the forces were replaced by F4 which was to be equilvalent to the initial forces, but of course that's not what it is asking, it is saying that F4 is added into the system to create equilibrium.

Thanks again,
Mitch.
And I misread the book answer as 22/21 when it is 92/21
 
gnits said:
And I misread the book answer as 22/21 when it is 92/21
That's a relief. Thanks for letting me know.
 
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