Equation for molar specific heat

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To derive the molar specific heat at constant volume for a mixture of n_1 moles of a monatomic gas and n_2 moles of a diatomic gas, the equation Q = C_v(n_1+n_2)*delta(T) is used. The specific heat for a monatomic gas is 3/2R, while for a diatomic gas, it is 5/2R. By combining these values, the overall molar specific heat can be expressed as C_v = (n_1*(3/2R) + n_2*(5/2R)) / (n_1 + n_2). This results in a final expression for the molar specific heat of the mixture in terms of n_1, n_2, and R. The discussion emphasizes the importance of correctly applying the specific heat values for each type of gas in the mixture.
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n_1 moles of a monatomic gas and n_2 moles of a diatomic gas are mixed together in a container. Derive an expression for the molar specific heat at constant volume of the mixture. Expression must be in terms of n_1, n_2, and the gas constant R.

I know that the molar specific heat of the entire mixture is Q = C_v(n_1+n_2)*delta(T). and my physics professor told me that I can use the equation Q = 3/2nR*delta(T) and set it equal to C_v(n_1+n_2)*delta(T) and somehow use that to solve for something, but I'm not sure what I can solve for. I keep getting C_v = 3/2R, but when I plug that in, the equation doesn't work ( 3/2R(n_1+n_2) is incorrect ). I would appreciate some help. Thanks
 
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The molar specific heat of a diatomic gas is 5/2R. Does this help?
 
Got it! Thanks!
 

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