Equivalent capaticnace, charge, voltage

AI Thread Summary
The discussion focuses on calculating the equivalent capacitance of a circuit and determining the charge and voltage across each capacitor. The user has made progress by adding capacitors in parallel and series, arriving at values of 13 and 35/12 for parts of the circuit. They seek clarification on how to proceed with the final calculations for capacitance. Another participant reassures them that they are on the right track and encourages them to continue with the series calculation. The conversation emphasizes the importance of understanding series and parallel connections in capacitor circuits.
JSmith2009
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Homework Statement


Find the equivalent capacitance of the circuit below. Also determine the charge of each capacitor and the potential difference across each capacitor.

http://img18.imageshack.us/img18/2616/physicss.jpg


Homework Equations


Q=VC

Parallel Ceq = C1+C2+C3
V1=V2=V3
Q=Q1+Q2+Q3

Series Ceq = (1/Ceq)=(1/C1)+(1/C2)+(1/C3)
Q1=Q2=Q3
V=V1+V2+V3

The Attempt at a Solution


I sort of figured out the equivalent capacitance. Adding the 3 in parallel as well as the two in series on the right side, you get 13 across the top and (35/12) on the right side. Then adding the 8 and (35/12) in parallel, you get (131/12). How do I figure out capacitance from there?

I *should* be able to figure out charge/voltage from there and if not, will come back.

Thanks much!
 
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JSmith2009 said:
How do I figure out capacitance from there?

All I can say is don't stop there. Now all you have left is the 13 capacitor and the 131/12 capacitor in series. Clearly you know what to do.
 
Well, I wasn't sure if it was in series or not. I don't know why, but for some reason my mind kept telling me that it wasn't a series connector.

I guess I just needed some reassurance. Thanks :)
 
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