Evaluating double integral - jacobian help

AI Thread Summary
The discussion focuses on evaluating a double integral using a coordinate transformation involving the Jacobian. The Jacobian was calculated as 4(x^2 + y^2), which simplifies the integral. Participants discussed determining the new limits for the transformed variables u and v, with u corresponding to x^2 - y^2 and v to 2xy. It was clarified that in the first quadrant, the limits for v range from 0 to infinity, while u varies from negative to positive infinity, represented by hyperbolae. The conversation concludes with confirmation of the limits for the transformation.
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Homework Statement



trying to evaluate the double integral from 0 to infinity and 0 to infinity of [(x^2 + y^2)/1 + (x^2-y^2)^2]e^-2xy dxdy

using the coordinate transformation u=x^2-y^2 and v=2xy



Homework Equations





The Attempt at a Solution



so i calculated the jacobian which looks nice 4(x^2+y^2)..can see some canceling there

just can't see what the new limits will be...

thanks for any help
 
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Hi bon! :smile:

(have an infinity: ∞ and try using the X2 tag just above the Reply box :wink:)

When you're trying to find new 2D or 3D limits, just draw the region, and then mark it with the "contour lines" of the new variables.

In this case, the region is the whole first quadrant …

now draw some typical curves for u = constant and for v = constant …

check that (u,v) is single-valued, and just read off the diagram what the lowest and highest "contour lines" are. :wink:
 


Ok thanks so i see that v goes from 0 to infinity...i just can't see u at the moment..

thanks
 
u = 0 is the straight diagonal line …

what are the other curves for u = constant in the first quadrant? :wink:
 


ahh hyperbolae..so would it be -infinity to + infinity?

thanks
 


is this right?
 
bon said:
ahh hyperbolae..so would it be -infinity to + infinity?

thanks

let's see …

each lower "hyperbola" is a quarter of a hyperbola, starting at the x-axis and finishing "at infinity", close to the diagonal …

so it goes from xy = 0 to xy = ∞ (and the same for the upper "hyperbolas").

So yes, x2 - y2 goes from -∞ to ∞, and for each value of x2 - y2, xy goes from 0 to ∞. :smile:
 


great thanks
 
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