Exam coming soon, need help with this question

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A body moves from point A at a constant velocity of 40 m/s, while another body starts from rest at A with an acceleration of 2 m/s² after a 10-second delay. To solve the problem, the equations of motion should be applied, specifically focusing on the time delay and how it affects the distance covered by both bodies. Visualizing the scenario with a distance-time graph can clarify the relationship between the two bodies' movements. Understanding the impact of the initial 10 seconds is crucial for determining when and where the second body catches up.
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Exam coming soon, need urgent help with this question!

Homework Statement


A body leaves a point A and moves in a straight line with a constant velocity of 40m/s. Ten seconds later another body which is at rest at A is given an accelleration of 2m/s2 and moves in the same direction as the first body. How long does it take the second body to catch up with the first? How far from A does this occur?


Homework Equations





The Attempt at a Solution

 
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Use these:
v=u+at
s=ut+0.5at^2
v^2=u^2+2as

and come back with specific doubts.:rolleyes:
 
I know I am suppsed to use those equations but i don't know how? I don't know what to do with the 10 seconds.
 
Draw a picture!

milan.007 said:
I don't know what to do with the 10 seconds.

Sometimes a picture makes things clearer.

Draw it for yourself (only roughly) on a graph (distance against time).

Then I think you'll see where the 10 seconds comes in. :smile:
 
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