Exam coming soon, need help with this question

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Homework Help Overview

The problem involves two bodies moving in a straight line, one with a constant velocity and the other starting from rest with a constant acceleration. The original poster seeks to determine the time it takes for the second body to catch up to the first and the distance from the starting point at which this occurs.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of kinematic equations and express uncertainty about how to apply them, particularly regarding the significance of the initial 10-second delay for the second body.

Discussion Status

Some participants have provided equations that may be relevant to solving the problem, while others suggest visualizing the scenario through a graph to clarify the role of the 10 seconds. There is an ongoing exploration of how to approach the problem without a clear consensus on the next steps.

Contextual Notes

The original poster has indicated urgency due to an upcoming exam, which may influence the nature of the discussion and the responses provided.

milan.007
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Exam coming soon, need urgent help with this question!

Homework Statement


A body leaves a point A and moves in a straight line with a constant velocity of 40m/s. Ten seconds later another body which is at rest at A is given an accelleration of 2m/s2 and moves in the same direction as the first body. How long does it take the second body to catch up with the first? How far from A does this occur?


Homework Equations





The Attempt at a Solution

 
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Use these:
v=u+at
s=ut+0.5at^2
v^2=u^2+2as

and come back with specific doubts.:rolleyes:
 
I know I am suppsed to use those equations but i don't know how? I don't know what to do with the 10 seconds.
 
Draw a picture!

milan.007 said:
I don't know what to do with the 10 seconds.

Sometimes a picture makes things clearer.

Draw it for yourself (only roughly) on a graph (distance against time).

Then I think you'll see where the 10 seconds comes in. :smile:
 

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