Exponential Rate Problem: Solving for x and Showing Convergence to pi

  • Thread starter Thread starter evolution685
  • Start date Start date
  • Tags Tags
    Exponential Rate
evolution685
Messages
10
Reaction score
0
first i had to show solve x′=sin(x) to get t=ln|(csc(x₀)+cot(x₀))/(csc(x)+cot(x))|

i did that.

next i need to show that for x₀=(π/4) you can solve x=2arctan(((e^{t})/(1+√2)))

what I've done so far is

t=ln|((csc(pi/4)+cot(pi/4))/(csc(x)+cot(x))|
t=ln|((2/sqrt(2)+1)/(csc(x)+cot(x))|
e^t=(2/sqrt(2)+1)/(csc(x)+cot(x))
csc(x)+cot(x)=(2/sqrt(2)+1)/e^t

and haven't been able to get any further. is this on the right track? how do i proceed?

and finally i need to show that x(t)→pi as t→∞.

the hint I've gotten is that it involves l'hopital's rule and maybe the equation

lim t->inf (k/(1+(k/x0 - 1)e^(-mt)-k))/e^(-mt)

i have no idea what this equation means or how it relates. anyone know?

thanks a million
 
Physics news on Phys.org
To simplify there's a trig identity that says arccot(a/2)=csc(a)+cot(a). For the limit, just look at a graph of arctan.
 
sweet. that saved me several hours of pounding my head.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top