Expressing phase space differential in terms of COM

ghostfolk
Messages
58
Reaction score
1

Homework Statement


The Hamiltonian for a single diatomic molecule of identical atoms is given as $$H=\dfrac{\vec{p_1}\cdot\vec{p_1}}{2m}+\dfrac{\vec{p_2}\cdot\vec{p_2}}{2m}+\dfrac{K}{2}(\vec{r_1}-\vec{r_2})\cdot(\vec{r_1}-\vec{r_2})$$. Find the grand canonical partition function for a gas of such molecules, neglecting the interactions between molecules.

2. Homework Equations

$$Z=\dfrac{1}{N!}\int\dfrac{d^3p_id^3x_i}{h}e^{-\beta H}$$

The Attempt at a Solution


I know that if we can express the momenta in terms of the center of mass coordinates and the relative coordinates, $$R=(r_1+r_2)/2$$ and $$r=r_1-r_2$$. However I am not sure how to express the differential in terms of the center of mass and relative coordinates.
 
Physics news on Phys.org
You have the relative coordinate r = r1-r2 and the COM coordinate R = (r1m1 + r2m2)/(m1+m2). It's easy to show that:
∂ /∂r1 = m1/(m1+m2)∂ /∂R + ∂ /∂r and
∂ /∂r2 = m2/(m1+m2)∂ /∂R - ∂ /∂r.
The Hamiltonian becomes
H(r,R) = -ħ2/(2M)(∂2 /∂R2 )- ħ2/(2μ))(∂2 /∂r2) + K/2(r⋅r)
where M = m1+ m2 and μ=(m1m2)/(m1+ m2).
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top