F=ma Physics Olympiad Exam question 19: Constant power

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Homework Help Overview

The problem involves a car accelerating from rest with a constant power output from its engine. The original poster seeks to determine the car's acceleration at a specific time, given its acceleration at an earlier time.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants suggest various relationships involving power, kinetic energy, and acceleration. Some propose using the equation for power in terms of kinetic energy over time, while others encourage equating constant values related to the problem's parameters.

Discussion Status

The discussion has generated multiple hints and suggestions for the original poster to explore, but there is no explicit consensus on a single approach. Participants are awaiting further input from the original poster before continuing the discussion.

Contextual Notes

Participants are operating under the assumption that energy loss due to friction can be ignored, which may influence their reasoning and approaches.

jerrylinew
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Homework Statement


A car has an engine which delivers a constant power. It accelerates from rest at time t = 0, and at t = t0 its acceleration is a0. What is its acceleration at t = 2t0? Ignore energy loss due to friction.


Homework Equations


P=W/t, W=Fd, F=ma


The Attempt at a Solution



substitute the last two equations into the first equation to get P=m*a*d/t=constant. m is always constant, so a*d/t = constant. I don't know what to do from here.
 
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Try also to use

P = (Kinetic energy)/Time

and see where that gets you.
 
you should try and think what is constant and then try to apply that here.

try to equate constant values .
 
P=f*v=ma*v
Try differentiating this and see what you get (don't forget the product rule)
 
Moderator's note:

Now that the OP has been given several hints, I urge people to refrain from giving further help until the OP responds.

Thank you for your cooperation.
 

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