(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two rubber bands stretched to the standard length cause an object to accelerate at 2 m/s^2. Suppose another object with twice the mass is pulled by four rubber bands stretched to the standard length. The acceleration of this second object is: ??

The correct answer is 2m/s^2.

2. Relevant equations

F = ma

a = F/m

3. The attempt at a solution

a = F/m

Therefore, a is inversely proportional to m.

a1/a2 = m2/m1

Second mass is twice the first mass.

a1/a2 = 2m/m

m's cancel out, leaving:

a1/a2 =2

Isolate a2:

a2 = a1/2

That would make my acceleration of the second object 1 m/s^2, not 2 m/s^2. Did I miss something?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# F=ma proportional reasoning

**Physics Forums | Science Articles, Homework Help, Discussion**