Faulty lamp because it short circuit

AI Thread Summary
The discussion centers on identifying a faulty lamp in a circuit using resistance measurements. It is determined that lamp C is faulty due to its short circuit, indicated by a measured resistance of zero. The resistance of a functioning lamp is established as 15 ohms, and when lamps A and B are connected in series, the combined resistance is 30 ohms, confirming that B is not faulty. The analysis reveals that in the fourth case, lamp C must be shorted, allowing current to bypass it entirely. Overall, the key conclusion is that a faulty lamp can either have infinite or zero resistance, with C exhibiting zero resistance in this scenario.
thoradicus
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Homework Statement


http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20%289702%29/9702_s06_qp_2.pdf

number 7a

Homework Equations


None really

The Attempt at a Solution


The answer is that C is the faulty lamp because it short circuit. But how do I know it is faulty?

Im quite sure it has something to do with the last row: open closed closed 15 ohm

Just realized it was a 1 word title :/
 
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The ohmmeter reads the resultant resistance between its terminals. Which lamp does it measure in the first case? So what is the resistance of one lamp? Which lamps are connected in series in the third case?

ehild
 


ehild said:
The ohmmeter reads the resultant resistance between its terminals. Which lamp does it measure in the first case? So what is the resistance of one lamp? Which lamps are connected in series in the third case?

ehild

For the 1st case it measures no lamps?
The resistance for 1 lamp is 15ohm.
A and B?>
 


Sorry, I wanted to ask the first case when S1 is closed. But it is right, the resistance of one lamp is 15 ohm. In the third case, A and B are connected in series, the resistances add up, and the meter measures 30 ohm, which is the resultant of two lamps in series. So lamp B is not faulty.

How are the lamps connected in the fourth case? What is the resistance of C when the resultant is 15 ohm?
ehild
 


ehild said:
Sorry, I wanted to ask the first case when S1 is closed. But it is right, the resistance of one lamp is 15 ohm. In the third case, A and B are connected in series, the resistances add up, and the meter measures 30 ohm, which is the resultant of two lamps in series. So lamp B is not faulty.

How are the lamps connected in the fourth case? What is the resistance of C when the resultant is 15 ohm?



ehild
ummm in parallel? I am not sure
Is it 0 for C?
 


B and C are connected in parallel, and A is in series with the resultant of B and C. Yes, the resistance of C has to be zero.

ehild
 


Ok, so let me get this right

the current passes through A but also passes through C only, because it is faulty so it has 0 resistance, so it was shorted?
 


thoradicus said:
Ok, so let me get this right

the current passes through A but also passes through C only, because it is faulty so it has 0 resistance, so it was shorted?

Yes. But a faulty lamp can have either infinite or zero resistance. If it is not shorted, the meter would read a resistance higher than 15 ohm. The measured resistance is 15 ohm, so leaving lamp A, the current goes through a short. Or: The resultant resistance of B and C in parallel has to be zero. That can happen only when C is a short (as B is not faulty).


ehild
 

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