Final Kinetic Energy and speed of three projectiles fired from a building's roof

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SUMMARY

The discussion centers on the final kinetic energy and speed of three projectiles (mA, mB, mC) launched from a building, all possessing the same initial kinetic energy. As they reach the ground, the kinetic energy remains constant due to the conservation of energy principle, where the initial kinetic energy plus potential energy equals the final kinetic energy. The projectile with the greatest mass (mA) will have the highest final kinetic energy, and all projectiles will attain the same increase in speed, calculated as vf = sqrt(2gh), upon hitting the ground.

PREREQUISITES
  • Understanding of kinetic energy (KE) and potential energy (PE) equations
  • Familiarity with the conservation of energy principle
  • Basic knowledge of projectile motion
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the conservation of mechanical energy in projectile motion
  • Learn about the effects of mass on kinetic energy and speed
  • Explore the equations of motion for projectiles
  • Investigate the relationship between height and potential energy in physics
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Students studying physics, particularly those focusing on mechanics and energy conservation, as well as educators seeking to clarify concepts related to projectile motion and energy transformations.

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Homework Statement



Three different mass projectiles, mA > mB > mC, are launched from the top of a building at different angles with respect to the horizontal. Each particle has the same initial kinetic energy.

Which particle has the greatest kinetic energy just as it hits the ground? Why?
Which particle has the greatest speed just as it hits the ground? Why?

Homework Equations



(KE + PE)i = (KE + PE)f
KE = .5 mv^2
PE = mgh

The Attempt at a Solution



I don't know if it is the particle that has the highest mass m or attains the highest height h. Obviously, the one that attains the highest point will have the highest final velocity. vf = sqrt(2gh)

My teacher said that's wrong and now I don't know what to put.
 
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Hint: What can you say about the kinetic energy of each projectile as it reaches the same level as when it was launched? At that point, think about potential energy.
 
Hmm that is very helpful. At the point where they were launched, the energy of each projectile would equal its initial kinetic energy. So the initial kinetic energy + mgh at that point would equal the total energy, so mA has the highest?
 
Yes, you are correct.

Each projectile will have its speed increased by (2gh)^.5 when it hits the ground. That implies something about which one is going the fastest when it hits.

This is all the assistance I can give. I'll be away from a computer for the next few days.
 

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