Find all nonisomorphic abelian gps

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Homework Statement


- List all nonisomorphic abelian groups of order 2^3 3^2 5


Homework Equations





The Attempt at a Solution


- Z_2^3 * Z_3^2 * Z_5 = (iso) Z_360.
Z_2^3 * Z_3 * Z_3 * Z_5 = (iso) Z_3 * Z_100
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I know ,
but why Z_360 , Z_3 * Z_100 are nonisomorphic to 2^3 3^2 5 ?
 
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Because Z_360 == Z_2^3 * Z_3^2 * Z_5, but Z_3 * Z_100 == Z_2^3 * Z_3 * Z_3 * Z_5.
 
Sorry, I don's understand it..
Z_2^3 * Z_3 * Z_3* Z_5 == Z_8 * Z_9 * Z_5 Is this nonabelian groups of order
2^33^25 ??
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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