Find Center of Mass of Homogeneous Semicircular Plate

  • Thread starter Thread starter team31
  • Start date Start date
  • Tags Tags
    Center Mass
AI Thread Summary
To find the center of mass of a homogeneous semicircular plate, integration is necessary, particularly considering the variable radius as slices are taken. The user is exploring the setup of two integrals: one for the radius and another for the y-coordinate of the center of mass (Ycm). In a separate question regarding a cube box, the user struggles to calculate the z-coordinate of the center of mass (Zcm) and attempts a complex method that yields an incorrect result. A simpler approach is requested for determining Zcm, while the user also confirms their earlier calculation for the semicircular plate's center of mass as 4R/3π. The discussion emphasizes the challenges and methods involved in calculating centers of mass for different shapes.
team31
Messages
10
Reaction score
0
Find the center of mass of a homogeneous semicircular plate, let R be the radius of the circle.
I have think I need to use ingergration to slove this problem, I'm stuck with that R is also changing as if I'm cutting little slices, so does that mean i have to set up two intergra, one for R solve that, and put it into another intergra which is for Ycm?

another question is there is a cube box with no top lays on a coordinate system x,y,z, z is vertical. and the side is 40 cm, I can find xcm=20 and ycm=20 very easily, but i had a hard time to find z, and i used harder way to find z, which is tp set zcm=x, and calculate the weight between the top half of the box and bottom half of the box,
40(40-x)+2(40-x)2=20*20+40x+40x.
from there I got Zcm=17.5, and that is not even the right answer, can u guys suggest a better and easier way for me to slove it?
 
Physics news on Phys.org
X=\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}\frac{xdm}{M}
 
huh, i got it, 4r/3pi is my answer, is that right?
 
could anybody give me a hint on my question #2, please
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Back
Top