Find Distance: Skydiver Jumping from 36000m in Stratosphere

  • Thread starter Thread starter KunwarS
  • Start date Start date
AI Thread Summary
A skydiver jumping from 36,000 meters in the stratosphere must consider wind effects on their horizontal displacement. The wind speed of 15 km/h from the North influences the diver's trajectory, even before reaching the troposphere at 15,000 meters. The discussion suggests that the wind should be accounted for throughout the fall, as it affects the air the skydiver descends through. It is implied that for calculations, the wind speed can be treated as constant across different heights. Understanding these dynamics is crucial for accurately determining the diver's landing position relative to the jump point.
KunwarS
Messages
1
Reaction score
0

Homework Statement


A sky diver jumps off a plane from a height of 36000 m (which is in the stratosphere). The wind is blowing at a rate of 15 km/h from the North. How far will the sky diver be from the point directly beneath him on Earth from when he jumped?

Homework Equations


a=v*t, v=s/t, Sin A/a = Sin B/b

The Attempt at a Solution


I have no idea how to factor in the wind. Should I even be considering the wind until the skydiver reaches the troposphere, which is at 15000 m?
 
Physics news on Phys.org
Well, the wind is moving the air the sky diver falls through. Does this affect the motion of the sky diver or not? (Hint: think about something light, like a piece of paper or a balloon.)

As for the other question, you are probably expected to use the same wind speed at all heights. That's based more on experience with how these problems usually turn out to be, than on what's the more physical scenario though.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Thread 'Egg Drop Challenge! Need ideas for winning designs'

I was thinking using 2 purple mattress samples, and taping them together, I do want other ideas though, the main guidelines are; Must have a volume LESS than 1600 cubic centimeters, and CAN'T exceed 25 cm in ANY direction. Must be LESS than 1 kg. NO parachutes. NO glue or Tape can touch the egg. MUST be able to take egg out in less than 1 minute. Grade A large eggs will be used.
View full post »

Similar threads

Relative Wind Problem (Modern Engineering Mathematics, 5th)
Replies
3
Views
2K
Freefall problem of a diver jumping horizontally upward
Replies
7
Views
3K
Velocity of wind based on the shape of a smoke trail
Replies
16
Views
2K
Calculating Velocity when Stuntman Jumps from 1.25m Height
Replies
30
Views
2K
Question on Terminal Velocity finding time
Replies
6
Views
2K
What Factors Affect the Speed of a Skydiver One Second After Jumping?
Replies
11
Views
3K
Kinematics -- flying a plane in the wind to a destination
Replies
3
Views
2K
How Do Two Divers' Speeds Compare When Jumping from a 3m Platform?
Replies
4
Views
3K
Vectors and Two Dimensional Motion
Replies
16
Views
2K
How Fast is the Airplane Flying Relative to the Air?
Replies
17
Views
4K

Hot Threads

Recent Insights

Back
Top