Find magnetic flux density B circulation in closed contour

AI Thread Summary
To find the magnetic flux density B circulation in a closed contour with a square conductor, the integral ∫B⋅dl can be expressed as μ0⋅j⋅a². The integration contour is identified as Γ, which is crucial for the calculation. The line integral of H over any section of the larger perimeter with zero current is zero, while the integral over the current-carrying sides yields ja³. The total circulation of H over the common sections results in 2ja³, leading to the conclusion that B equals μ0H. Understanding these relationships is essential for solving the problem accurately.
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Homework Statement


Find magnetic flux density B circulation in closed contour. The countour consists of square with a perimeter of 4b. It includes a square conductor with a perimeter of 4a. A homogenic current flows through a conductor with a current density of j.
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Homework Equations


∫B⋅dl=μ0⋅I[/B]

The Attempt at a Solution


I get this equation ∫B⋅dl=μ0⋅j⋅a2 but the answer says that the integration contour is Γ. How do I get the Γ? ΓB⋅dl=μ0⋅j⋅a2
 
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Well, since it's been nearly 120 hrs (5 days) with no other posters,I will suggest:
(1) line integral of H over ANY section of the large perimeter WITH ZERO CURRENT EVERYWHERE = 0. This includes the two "a" sections common to the large & small perimeters.
(2) line integral over any one of the four current-carrying section sides (by Ampere's law) = ja2(a) = ja3.
(3) Thus the circulation of H over the two common "a" sections = 2ja3 and of course B = μ0H.
(4) Add (3) to (1) and you get the answer of (3).
 
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