A light string is wrapped around the outer rim of a solid uniform cylinder of diameter 75.0cm that can rotate without friction about an axle through its center. A 3.00kg stone is tied to the free end of the string. When the system is released from rest, you determine that the stone reaches a speed of 3.50m/s after having fallen 2.50m.
What is the mass of the cylinder?
net torque = I * alpha
I = m * r^2 / 2
The Attempt at a Solution
For this problem I have no idea where to start. I am completely lost...I know there should be some Omega calculations a theta calculations and I need to find impulse along with torque...any help is appreciated!