Find Net Couple with P=0 | Magnitude & Direction of Axis

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SUMMARY

The discussion focuses on finding the net couple when P=0 by replacing two remaining couples with a single equivalent couple, detailing its magnitude and direction. The position vectors for points B and D are given as rb=0.3i and rd=0.16j+0.17k, respectively. The participant initially calculated the components of a 34N force incorrectly, leading to an erroneous moment calculation of 7.59. The correct approach involves determining the direction of the forces based on the coordinates of points D and E, ensuring accurate vector representation.

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utkarshakash
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Homework Statement


If P=0, replace the two remaining couples with a single equivalent couple, specifying its magnitude and the direction of its axis.


The Attempt at a Solution



Position vector of B(rb)=0.3i
Similarly, rd=0.16j+0.17k

∠GCF=atan(16/30)=28.07°
∠DEF=atan(DF/FE)=45°
Then I tried to resolve the forces into its individual components. For 34N force applied at B, in vector form,

34 \cos 28.07 \hat{i}-34 \sin 28.07 \hat{j}-34 \cos 45 \hat{k}
For the other force at B, I can write -18k.
At D, -34 \cos 28.07 \hat{i}+34 \sin 28.07 \hat{j}+34 \cos 45 \hat{k}

Now I take moments of all the above forces about the origin which gives me
1.13i + 7.51j

the magnitude of which is given by \sqrt{1.13^2+7.51^2} = 7.59

which is incorrect according to answer key.
 

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Are you sure angle DEF is 45 degrees? It doesn't look it from the figure.
 
You calculated the components of the 34 N force incorrectly. The 34 N forces are parallel to the vector connecting D and E or F and B. Find the direction of those vectors from the coordinates of the points. Multiply the magnitude of the force with the unit vector in the appropriate direction. ehild
 

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