Find Net Electric Field Magnitude & Direction in an Equilateral Triangle

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SUMMARY

The discussion focuses on calculating the net electric field at the centroid of an equilateral triangle. The correct formula for the electric field is given by the equation E = kq/r² âr, where k is Coulomb's constant, q is the charge, and r is the distance from the charge to the point of interest. Additionally, determining the direction of the electric field requires breaking down the components into x and y directions.

PREREQUISITES
  • Understanding of Coulomb's Law
  • Familiarity with vector components
  • Knowledge of electric field concepts
  • Basic trigonometry for angle calculations
NEXT STEPS
  • Study the application of Coulomb's Law in electric field calculations
  • Learn about vector addition in electric fields
  • Explore the concept of electric field lines and their directions
  • Investigate the effects of multiple charges on net electric fields
USEFUL FOR

This discussion is beneficial for physics students, electrical engineers, and anyone interested in understanding electric fields in geometrical configurations.

kevykevy
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Find the magnitude and direction of the net electric field at the centre (or centroid) of the triangle.

The triangle is equilateral and the point of reference is in the middle of the triangle.

What I want to know is what equation do I use to figure this out?

At first I thought it was: Fnet = kq1q2/r^2

Is that right?, if not can you tell what to use?
 
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That's almost right...the question asks for the net electric field, which means you have to use a vector, not just the magnitude as you've shown.

\vec{E} = \frac{kq}{r^2}\hat{r}
 
Also, how do I find the direction of the field?

Do I have to use some sort of x and y component breakdown?
 
kevykevy said:
Do I have to use some sort of x and y component breakdown?

That's right.
 

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