Find the acceleration vector of the mass

Click For Summary
To find the acceleration vector of a 10.0 kg mass acted upon by two forces, the net force was calculated as (6.0x - 1.6y) Newtons. The acceleration was then derived by dividing this net force by the mass, resulting in a proposed acceleration of a = (0.6x - 0.16y) m/s². However, there was a correction needed regarding the division by mass, as it was suggested that the magnitude of the net force should first be calculated and then divided by the mass. The discussion emphasized the importance of correctly applying vector components and magnitude calculations to arrive at the accurate acceleration vector. The final conclusion is that the initial acceleration calculation needs reevaluation based on proper vector analysis.
XwakeriderX
Messages
49
Reaction score
0

Homework Statement


Two forces are acting on a 10.0 kg mass. The forces are:
F1 = (12.3 x - 13.5 y) Newtons where x and y are unit vectors
F2 = ( -6.30x + 11.9y) Newtons

A) Find the acceleration vector of the mass. Express your answer in unit vector
form.



Homework Equations


F=MA


The Attempt at a Solution


I added the two vectors getting
(6.0x-1.6y) Newtons then i divided it by the mass to get the acceleration

So my final answer is a= (0.6x-0.16y) m/s2

is this correct?
 
Last edited:
Physics news on Phys.org


XwakeriderX said:
So my final answer is a= (0.6x-0.16y) m/s2

is this correct?

You divided each vector (x and y) by ten, meaning that the result was that you were dividing it by ten, twice, resulting in 100.

Ex: if your vector was 20x + 20y, that magnitude is 400, so dividing each component by 10,
2x + 2y, you get a magnitude of 4.

You need to find the magnitude of 6x - 1.6y (Pythagorean) and divide THAT by ten, then use trigonometry to find the x,y components at that magnitude.
Or, a shortcut is to divide each component by sqrt(10) since the sqrt(10) ^ 2 is 10, so by dividing by the sqrt(10) twice (once to each component) you are ultimately dividing by 10.
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
Replies
23
Views
2K
  • · Replies 25 ·
Replies
25
Views
1K
  • · Replies 17 ·
Replies
17
Views
3K
Replies
44
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
1
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K