Engineering Find the electric field intensity due to a point, line, and plane

Click For Summary
The discussion focuses on calculating the electric field intensity due to different charge distributions, specifically a point charge, line charge, and plane charge. The user presents their calculation for E2 and seeks confirmation on its accuracy, stating it as E2=2*10^-9*(1/√2ŷ+1/√2ž)/(2πεo√2). There is a clarification regarding the notation, confirming that d^ represents a unit vector. The conversation emphasizes the importance of correct vector representation in electric field calculations. Overall, the thread highlights the need for peer validation in physics problem-solving.
falyusuf
Messages
35
Reaction score
3
Homework Statement
Attached below.
Relevant Equations
Attached below.
Question:
1637713795779.png

My attempt:
1637713833937.png

1637713851937.png
Could someone please confirm my answer?
 
Physics news on Phys.org
In my opinion E2=2*10^-9*(1/√2ŷ+1/√2ž)/(2πεo√2).
Otherwise everything is correct
 
Babadag said:
In my opinion E2=2*10^-9*(1/√2ŷ+1/√2ž)/(2πεo√2).
Otherwise everything is correct
So d^ is a unit vector, right?
 
Yes
 
Thread 'Full bridge circuit with inductor and resistor'
The above is the circuit i am calculating the inductor current. During the positive half of the sine input D1 and D3 are conducting so the circuit becomes My calculations are as below Are the above equations ok? When transitioning from +Ve cycle to -Ve sine wave does the above equations still applicable? During the negative cycle the diodes D2 and D4 are conducting and the current direction is going into the inductor same as when diodes D1 and D3 are conducting. According to me the same...