Find the resistance between the top and bottom faces of the cylinder

AI Thread Summary
To find the resistance between the top and bottom faces of a right circular aluminum cylinder, the mass, density, and resistivity of aluminum are used. The height of the cylinder is determined to be 0.0554 m by solving the density equation. Substituting this height into the resistance formula yields an initial incorrect resistance value of 1.169e-7 OHM, later corrected to 3.65586e-8 OHM after recalculating. The discussion emphasizes the importance of correctly applying the resistance formula and using the correct values for resistivity, length, and area. Clarification on the relationship between radius and height is also sought, as the homework is due soon.
mba444
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Homework Statement



A 361 g mass of aluminum (Al) is formed into
a right circular cylinder shaped so that its
diameter equals its height.
Find the resistance between the top and
bottom faces of the cylinder at 20◦C. Use
2700 kg/m3 as the density of Al and
2.82 × 10−8 OHM· m as its resistivity. Answer
in units of
OHM.

Homework Equations


R= raw *(L/A)
D=(m/v)
height = diameter ... therefore r will (h/2)
V=pi*r^2*h

The Attempt at a Solution




what i did is that i solved for the height by substituting it in the density problem getting D(given)= M(given)/(Pi*(h/2)^2*h) .. which after solving is h= (1.444/(2700*Pi))^(1/3)
after that i substitute it back into the resistance equation.


Im stuck ad i eed your help please
thanx i advance
 
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Hi mba444! :smile:

(have a pi: π and a rho: ρ and try using the X2 tag just above the Reply box :wink:)
mba444 said:
… what i did is that i solved for the height by substituting it in the density problem getting D(given)= M(given)/(Pi*(h/2)^2*h) .. which after solving is h= (1.444/(2700*Pi))^(1/3)
after that i substitute it back into the resistance equation.

Well, that looks ok so far …

what number did you get, and what did you get next? :smile:
 
i got for h .. 0.0554m
after substituting into the R equation i got 1.169e-7


but my answer is wrong !
 
I think you need to use the Callendar–Van Dusen equation [which is a relation between temperature and resistance]
 
mba444 said:
i got for h .. 0.0554m
after substituting into the R equation i got 1.169e-7

I get your h, but not your R …

how do you get 1.169e-7 ?
 
ignore the previous value i think its a calculation mistake
i calculated it again i got 3.65586e-8
is it right ??
 
mba444 said:
ignore the previous value i think its a calculation mistake
i calculated it again i got 3.65586e-8
is it right ??

how did you get it?
 
R= (2.82e-8)[(0.055)/(PI*(2*0.055)^2)]

radius = 2* h
 
mba444 said:
R= (2.82e-8)[(0.055)/(PI*(2*0.055)^2)]

radius = 2* h

uhh? :redface: radius = h/2

(and what happened to that π I gave you?)
 
  • #10
ya since in the question they told us that the height equal the diameter
 
  • #11
i really don't understand .. my home work is due today .. and i really feel lost
 
  • #12
mba444 said:

Homework Equations


R= raw *(L/A)

What values are you using for raw, L, and A?
 
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