Find torque of a ball on the end of a light rod

AI Thread Summary
The discussion focuses on calculating the moment of inertia and torque for a ball on a rod rotating in a circle. The moment of inertia was correctly calculated as 0.99 kg*m^2. To find the torque needed to maintain constant angular velocity against air resistance, the relationship between force and torque is emphasized. The torque is determined by multiplying the air resistance force by the radius, leading to the conclusion that the torque must counteract the air resistance. Understanding these concepts is crucial for solving the problem accurately.
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Homework Statement



A small 1.25 kg ball on the end of a light rod is rotated in a horizontal circle of radius 0.890 m.
(a) Calculate the moment of inertia of the system about the axis of rotation.
____kg*m^2
(b) Calculate the torque needed to keep the ball rotating at constant angular velocity if air resistance exerts a force of 0.0800 N on the ball.
____m*N

Homework Equations



a) kg*m^2
b) kg*m^2-air resistance (dont know the formula; just a guess)

The Attempt at a Solution



a) 1.25*.89^2=.99kg*m^2 (i was able to figure out this answer)
b) 1.25*.89^2-.08=.91m*N
 
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Hint: air resistance is a force, you are required to find torque. how do u corelate them?
 
Do you know how to find find the Moment of inertia?
 
You got the moment of inertia right.
Carefully consider what forces it faces when moving at constant angular velocity.
 
Find the torque which is applied by the air on the object.The same amount of torque should be applied in the opposite direction in the opposite direction.

Torque = force * radius
 
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Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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