(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find the viscosity of water given that;

flow rate ([tex]cm^3 s^{-1}[/tex]) = 2.0

height from tube (m) = 0.1

l (m) = 0.2

r (mm) = 1

[tex]\rho[/tex] = 1000

g = 9.81

Using the equations;

x = [tex]\frac{Flow Rate}{Height}[/tex]

x = [tex]\frac{\pi \rho gr^4}{8l\eta}[/tex]

3. The attempt at a solution

Okay so first, and the most important bit I don't know if I'm doing right I convert the flow rate from [tex]cm^3 s^{-1}[/tex] to [tex]m^3 s^{-1}[/tex] by multiplying by [tex]10^{-6}[/tex]

So flow rate is now [tex]2 * 10^{-6} m^3 s^{-1}[/tex] ***I don't know if that bit is correct.***

Then x = [tex]\frac{2 * 10^{-6}}{0.1} = 2 * 10^{-5}[/tex]

and [tex]2 * 10^{-5} = \frac{\pi \rho gr^4}{8l\eta}[/tex]

After re-arranging and substituting I get;

[tex]\eta = 9.6*10^{-4}[/tex]

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If anyone could check my answer it would be greatly appreciated I haven't done physics for so long I've pretty much forgotten everything.

Thanks in advance

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# Homework Help: Find Viscosity

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