Find voltage gain and input resistance for op-amp

AI Thread Summary
The discussion focuses on calculating input resistance and voltage gain for ideal operational amplifiers (op-amps) in inverting configurations. The input resistance is consistently identified as 10k ohms, and the voltage gain is calculated as -10 based on the resistor values. Participants clarify that resistors connected to ground can often be ignored in these calculations due to the virtual ground property of ideal op-amps, although this simplification may not always hold true. The conversation emphasizes understanding the implications of virtual ground in high-gain op-amps with negative feedback. Overall, the calculations and concepts surrounding op-amps are reinforced through collaborative problem-solving.
ongxom
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Homework Statement


Find the input resistances and voltage gains for those ideal op amps
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Homework Equations





The Attempt at a Solution


The original inverting circuit look like this :
jt260xU.png

we already have the equations :
input resistance = 10k
voltage gain = -r2/r1 = -10
For the first circuit :
it still a inverting op amps, does the red marked 10k resistor get involved with input resistances ? I think it's not because it connected to the ground (virtual ?). R2 is 100k so the equation for voltage gain remains the same as the original circuit .
Second circuit:
there is no current in red marked 10k resistor, input resistance is unchanged (10k), voltage gain remains (-10k)

I find it is difficult to calculate using op amps characteristics, can I use voltage node method to find the voltage gain, which node should I choose. Are those ground connected resistor have no effect on the circuit input resistances and voltage gain at all ?
 
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You are correct that because of the virtual ground property (especially with ideal opamps), the input resistances of these circuits is 10kOhms. You have a typo in the gains, however. Can you see what your typo is?
 
berkeman said:
You are correct that because of the virtual ground property (especially with ideal opamps), the input resistances of these circuits is 10kOhms. You have a typo in the gains, however. Can you see what your typo is?

Yes, for the second circuit the gain is -10.
 
So can we say in those cases : In an inverting op-amp, any resistors connected to the ground can be ignored when calculate ?
 
ongxom said:
So can we say in those cases : In an inverting op-amp, any resistors connected to the ground can be ignored when calculate ?

I wouldn't say that -- it's a bit too simplified and not always true. Instead, understand what the "virtual ground" means. Can you tell us what is going on with the "virtual ground" property of a high-gain opamp with negative feedback means?
 
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