Finding a function in x,y from function in polar coordinates

sara_87
Messages
748
Reaction score
0

Homework Statement


v is in polar coordinates and i want to fin u(x,y) knowing that v(r,theta)=u(rcos(theta),rsin(theta))
therefore, u(x,y)=v(sqrt(x^2+y^2), arctan(y/x))
v(r,theta) = 9+18cos(2(theta))-9sin(4(theta))
question: what is u(x,y)?

Homework Equations





The Attempt at a Solution



u(x,y)=9+18cos(2arctan(y/x))-9sin(4arctan(y/x))

Is this correct and can i simplify this more?
Thank you.
 
Physics news on Phys.org


It's correct, but you can simplify a lot more. I would use double-angle formulas to express \sin(4\theta) and \cos(2\theta) in terms of \sin(\theta) and \cos(\theta). Then I could substitute \theta=\tan^{-1}(y/x) and work the resulting expressions into algebraic expressions.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top