Finding a Particle's Position with Given Velocity and Time

[ms245004]

Solving for position... please help

Homework Statement

A particle's position on the x-axis is given by the function f(x) = (t^2 - 2t +4) where t is given in s. Where is particle at v= 4m/s?

Homework Equations

f(x) = (t^2 - 2t +4)
sf = si + vi(tf -ti) + .5a(tf-ti)^2

The Attempt at a Solution

d/dx f(x)= 2t - 2 = 4
2t = 6
t = 3
sf= 0 + 0(3) + .5(4/3)(3^2)

 

[Redbelly98]

Welcome to Physics Forums

Homework Statement

A particle's position on the x-axis is given by the function f(x) = (t^2 - 2t +4) where t is given in s. Where is particle at v= 4m/s?

Homework Equations

f(x) = (t^2 - 2t +4)
sf = si + vi(tf -ti) + .5a(tf-ti)^2

The Attempt at a Solution

d/dx f(x)= 2t - 2 = 4
2t = 6
t = 3

Looks good so far.

sf= 0 + 0(3) + .5(4/3)(3^2)

Where does that come from? Just use the f(t) given in the problem statement and the value of t you found.

 

[ms245004]

Thank you so much. That worksed perfectly now.