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ms245004
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Solving for position... please help
A particle's position on the x-axis is given by the function f(x) = (t^2 - 2t +4) where t is given in s. Where is particle at v= 4m/s?
f(x) = (t^2 - 2t +4)
sf = si + vi(tf -ti) + .5a(tf-ti)^2
d/dx f(x)= 2t - 2 = 4
2t = 6
t = 3
sf= 0 + 0(3) + .5(4/3)(3^2)
Homework Statement
A particle's position on the x-axis is given by the function f(x) = (t^2 - 2t +4) where t is given in s. Where is particle at v= 4m/s?
Homework Equations
f(x) = (t^2 - 2t +4)
sf = si + vi(tf -ti) + .5a(tf-ti)^2
The Attempt at a Solution
d/dx f(x)= 2t - 2 = 4
2t = 6
t = 3
sf= 0 + 0(3) + .5(4/3)(3^2)