Finding an unknown resistance in an Electric Circuit

AI Thread Summary
When two resistors are connected in series to a 110-V line, they consume one-fourth the power compared to when connected in parallel. The known resistor value is 2.0 kΩ, and the goal is to find the resistance of the unknown resistor. Attempts to solve the problem resulted in negative values, indicating a miscalculation. The discussion suggests using symbolic expressions for power in both configurations and taking their ratio to establish the relationship needed to solve for the unknown resistance. This approach aims to clarify the power equations and correct the previous errors in calculation.
mlostrac
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Homework Statement


When connected in series to a 110-V line, two resistors use one-fourth the power
that is used when they are connected in parallel. If one resistor is
2.0 kΩ, what is the resistance of the other?


Homework Equations


1/Rt = 1/R1 +1/R2 (total resistance in parallel)
Rt = R1 + R2 (resistance in series)

Power = Current x Voltage


The Attempt at a Solution



So far my attempts have fizzled, ending with negative numbers.

Heres what I did:
1) Set the two hypothetical circuits (series and parallel) equal to each other by isolating the power:

P1 = 110^2/0.25(R1+R2)
P2 = 110^2(R1+R2)

And then isolating for R2 and solving (since we have R1 = 2000 ohms)

I ended up doing the quadratic equation and getting two negative numbers...

Any help would be appreciated :)
 
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mlostrac said:
P1 = 110^2/0.25(R1+R2)
Can you show why it this true?
P2 = 110^2(R1+R2)
The term R1+R2 must be in the denominator.

Anyway, I suggest that you work this symbolically. Find expressions

Pseries = V2/Req,series
Pparallel = V2/Req,parallel
then take the ratio and say
Pseries/Pparallel = 1/4.
 
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