Finding Coefficient of Kinetic Friction in a Pulley/Tension Problem

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AI Thread Summary
The discussion revolves around a physics problem involving two masses and a pulley system, where the goal is to find the coefficient of kinetic friction. The user initially calculated an incorrect negative value for the coefficient but later corrected it to 0.287 after re-evaluating their calculations. There was a focus on the importance of Free Body Diagrams (FBDs) in solving the problem, with some debate on whether the user had correctly analyzed their FBDs. Ultimately, the mentor emphasized the need for accurate arithmetic rather than issues with the FBDs. The thread concluded with a warning about further discussions on the topic.
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Homework Statement


I have a problem about two masses: m1 sitting on a table and m2 hanging off the end of th table across a frictionless pulley. There is friction between m1 and the table, however. The system is released from rest and m2 falls 1 meter in 1.2 seconds. m1=10.0 kg, m2=5.00 kg. find the coefficient of kinetic friction.

Homework Equations


I used x=.5at^2 to find a. I used m2g - T = m2a for m2 with down being positive and up being negative. And I used T - (mu)m1g = m1a for m1 with positive being the direction toward the end of the table.

The Attempt at a Solution


I used x=1 meter, t = 1.2 seconds in the first equation and solved for a to get a = 1.39 m/s^2. Then I solved the next two equations for T, set them equal to each other, then solved for mu to get mu = (m2g - m2a - m1a) / (m1g). This gave me a negative value for mu (-0.163) and I know that mu should be positive. Thanks for your help.
 
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Please show your arithmetic for this: mu = (m2g - m2a - m1a) / (m1g)

Chet
 
Lets see some FBD's first.
 
ME_student said:
Lets see some FBD's first.
He obviously used some correct FBDs, or he couldn't have written down the two force balance equations correctly.

Chet
 
Chestermiller said:
Please show your arithmetic for this: mu = (m2g - m2a - m1a) / (m1g)

Chet
(5*9.8 - 5*1.39 - 10*1.39) / (10*9.8) = - 0.163

Alright. I just found my mistake. I don't know what I did on the calculator last night, but I kept getting -0.163. Now I get the correct value of 0.287. Thanks for your help. By the way, what are FBDs?
 
cdenne said:
By the way, what are FBDs?
Free Body Diagrams. You obviously used these to get your force balances.

Chet
 
Chestermiller said:
Free Body Diagrams. You obviously used these to get your force balances.

Chet
Thank you very much for your help.
 
Chestermiller said:
Free Body Diagrams. You obviously used these to get your force balances.

Chet

OP didn't know what a FBD was so I was going to start helping him/her by having him/her draw some FBD. BTW Mr. Chet if he used correct FBD's he wouldn't be here asking us questions. Obviously OP must have analyzed something wrong on his/her free body diagram.
 
ME_student said:
OP didn't know what a FBD was so I was going to start helping him/her by having him/her draw some FBD. BTW Mr. Chet if he used correct FBD's he wouldn't be here asking us questions. Obviously OP must have analyzed something wrong on his/her free body diagram.
Dear ME_student,

I stand by what I said, to wit: If he hadn't drawn proper free body diagrams, he would not have been able to write down the force balance equations correctly (which he was able to do). His difficulty was not in drawing free body diagrams and developing the force balance equations, but in solving the force balance equations. So, obviously OP must not have analyzed something wrong on his/her free body diagram. Based on 50 years of engineering experience, this is the determination that I made. When you have 50 years of experience, come back and we can discuss this further. In the meantime, this thread is Closed.

If you want to discuss the issue further, you can contact me via private conversation. But be advised that, as a Mentor, I'm beginning to get an itchy Warning finger.

Chet
 
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