Finding factors in order to use U sub

  • Thread starter Thread starter TheKShaugh
  • Start date Start date
  • Tags Tags
    Factors
TheKShaugh
Messages
22
Reaction score
0

Homework Statement




\displaystyle{\int}\dfrac{x}{\sqrt{x^2+x+1}}~dx =<br /> <br /> \displaystyle{\int}\dfrac{(x+\frac 1 2)-\frac 1 2}{\sqrt{(x+\frac 1 2)^2+(\frac {\sqrt 3} 2)^2}}~dx

Homework Equations



Given.

The Attempt at a Solution



The solution is given, but I'm not sure how it was found. Is there a method for finding those factors or is it trial and error/intuition?
 
Physics news on Phys.org
TheKShaugh said:

Homework Statement




\displaystyle{\int}\dfrac{x}{\sqrt{x^2+x+1}}~dx =<br /> <br /> \displaystyle{\int}\dfrac{(x+\frac 1 2)-\frac 1 2}{\sqrt{(x+\frac 1 2)^2+(\frac {\sqrt 3} 2)^2}}~dx

Homework Equations



Given.

The Attempt at a Solution



The solution is given, but I'm not sure how it was found. Is there a method for finding those factors or is it trial and error/intuition?
There is a method. They are completing the square in the quadratic in the denominator.
x2 + x + 1 = x2 + x + (1/4) + (1 - 1/4)
= (x + 1/2)2 + 3/4
= (x + 1/2)2 + (√(3)/2)2

Then they are working with the numerator to get it as you see it in the expression on the right of what you posted.
 
  • Like
Likes 1 person
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top