Finding Force of Contact: 2kg and 3kg Blocks with 10N Horizontal Force

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SUMMARY

The discussion focuses on calculating the force of contact between two blocks, A (2 kg) and B (3 kg), subjected to a horizontal force of 10N. The correct force with which block B resists the pressure from block A is determined to be -6N. The participants emphasize the importance of free-body diagrams (FBDs) to visualize the forces acting on each block and the system as a whole. The acceleration of the system is calculated to be 2.0 m/s², which is crucial for understanding the interaction between the blocks.

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  • Understanding of Newton's laws of motion
  • Ability to draw and interpret free-body diagrams (FBDs)
  • Basic knowledge of force and acceleration calculations
  • Familiarity with frictionless surfaces in physics
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  • Study the application of Newton's second law in multi-body systems
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of contact forces in frictionless environments.

aishax
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A 2-kg block A and a 3-kg block B are in contact on a frictionless table. A horizontal force of 10N is applied to A. Find the force with which B resists the pressure of A.

The answer is -6N. I realize this is a very simple question, I would just like to understand how to get the solution. Thanks in advance :)
 
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Hi aishax, welcome to PF.

Start with drawing some free-body diagrams:
- One of the complete system (A + B)
- One of A only
- One of B only
Hint: The force felt by B must be the amount that makes it accelerate at the same rate as A and as A+B.

What are the "external forces" in each case?
 
Hello mezarashi :)

Alright, I drew each of those FBDs. I found the acceleration of the system, which was 2.0 m/s^2. I used the acceleration, and found the Fapp on mass A, which was 4.0 N. And Fapp for mass B is 6.0 N.

The external forces are Force normal, and force applied. I'm still a tad lost on the concept still, unfortunately.
 
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