How Do I Calculate the Value of g for a Pendulum?

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To calculate the value of g for a pendulum, the equation T = 2π√(l/g) is used, where T is the period and l is the length. The user plotted T^2 against l and found the gradient, questioning if this gradient directly provides the value for g. A suggested rearrangement of the equation is g = l / (T^2 / (2π)^2), indicating that the user may have overlooked squaring the 2π factor. The gradient of 16 was noted as potentially too high for g, prompting a recommendation to double-check the algebra for accuracy. Ensuring correct calculations is crucial for obtaining a realistic value for g.
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Homework Statement



I need to work out g for a pendulum. I have values for length (l) and time (T^2)

Homework Equations



T= 2 pi sqroot (l/g)

The Attempt at a Solution



I have plotted a graph of T^2 against l found the gradient of the line is this the value for g or if not do I need to rearrange the equation making g the subject ?

I am not too strong on algerbra and I came up with g = l / (T^2 / 2 pi^2)

but this gives me a silly small amount for g.

the gradient of my graph is 16 which is also a little high for g?
 
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Double check your algebra...did you forget to square the 2 factor also? I think so, see if your answer makes sense then... hope that helps.
 
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