Engineering Finding i(t) (Source Free RL Circuit)

  • Thread starter Thread starter salman213
  • Start date Start date
  • Tags Tags
    Circuit Rl circuit
AI Thread Summary
The discussion focuses on calculating the current i(t) in a source-free RL circuit, starting with the initial current i(0) of 5mA. The equation derived for the circuit is i(t) = (5x10^-3)e^(-t)/T, where T is determined as L/Req. The equivalent resistance Req is calculated to be 3/4k Ohms. Participants confirm that the switch remains closed for a long time before opening at t=0, validating the approach taken. Overall, the calculations and understanding of the circuit behavior are affirmed.
salman213
Messages
301
Reaction score
1
1. http://img529.imageshack.us/img529/6205/87421877rv5.jpg [/URL]3. First I found i(0)

the equation for a source free RL circuit is

i(t) = i(0)e^(-t)/T

T = L/ReqSince the inductor will be shorted when t<0, i(0) must be 5mA.

Now to find Req I added series and parallel appropriately to find

Req = 3/4k Ohms

so my equation is

i(t)= (5x10^-3)e^(-t)/T
where T = (1x10^-3)/(3/4x10^3)can someone please check that, Thanks!
 
Last edited by a moderator:
Physics news on Phys.org
By that arrow pointing to t=0, do you mean that the switch is closed for a very long time for t<0 and is opened at t=0?
 
ya for a very long time (t<0) the switch is "horizontal" then at t=0 it is moved to the lower point.
 
Yeah I got the same answer.
 
ok great, thanks!
 

Similar threads

Replies
10
Views
2K
Replies
2
Views
2K
Replies
2
Views
9K
Replies
1
Views
12K
Replies
46
Views
10K
Replies
13
Views
2K
Replies
2
Views
2K
Back
Top