Finding Initial Speed: A Basic Physics Problem Solved

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SUMMARY

The discussion focuses on solving a basic physics problem regarding initial speed using kinematic equations. The problem states that a car accelerates at 2.5 m/s² for 6 seconds, reaching a final speed of 60 m/s. The initial speed can be calculated using the formula v_f = v_i + Δv, where Δv is the change in speed, determined to be 15 m/s. The solution confirms that for positive acceleration, the initial speed is 45 m/s, and for negative acceleration, it is 75 m/s.

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  • Understanding of basic kinematics
  • Familiarity with the equation v_f = v_i + Δv
  • Knowledge of acceleration and its units (m/s²)
  • Ability to manipulate algebraic equations
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  • Study the concept of kinematic equations in detail
  • Learn how to rearrange equations for different variables
  • Explore examples of positive and negative acceleration scenarios
  • Review additional resources on motion and speed calculations
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Students in high school physics, educators teaching kinematics, and anyone looking to strengthen their understanding of motion and acceleration concepts.

Greenjacket
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[SOLVED] Basic Initial Speed Problem

Hello,
I've just picked up physics in year 10 and I'm keen to get started. So far I've been fine; I've been taught how to find velocity and acceleration of certain objects, but I'm unsure how to re-arrange the equations I've learned to solve other problems.

Homework Statement


After 6 seconds of acceleration at 2.5ms-2, a car is moving at 60ms-1. What was the initial speed of the car if the acceleration was:
a. Positive
b. Negative

Homework Equations


I think the equation I should use is a=V-U/t (must learn LaTeX...), but I have a feeling I have to re-arrange it somehow.

The Attempt at a Solution


If I multiply the time by acceleration (6x2.5ms-2), I get the change in speed(15ms-1) right? Also, subtracting the initial speed from the final speed gives me, again, the change in speed (which I don't know) right? If I use a trial-and-error method and simply guess the figures, I'd most likely get it wrong. Please help. I'm not expecting anyone to give me the exact answer, but if someone could point me in the right direction it would be greatly appreciated.
 
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Greenjacket said:
If I multiply the time by acceleration (6x2.5ms-2), I get the change in speed(15ms-1) right?
Right. The magnitude of the change in speed is 15 m/s. If the acceleration is positive, the change is +15 m/s; if negative, -15 m/s.

The final speed is initial speed + change:
v_f = v_i + \Delta v

You can use that to solve for the initial speed for both case.

A summary of kinematic formulas is given here: https://www.physicsforums.com/showpost.php?p=905663&postcount=2"
 
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Thanks Doc!
 

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