Finding intervals of increasing, decreasing, concavity and inflection points

ryan.1015
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Homework Statement



let g(x)=2x^5-10x^3=15x-3. find the intervals on which G is increasing and decreasing. and find the intervals of concavity and the inflection points

Homework Equations





The Attempt at a Solution


i know how to find the increasing and decreasing intervals. i just can't figure out where the graphs cross the x axis. and the concavity intervals i can't figure out
 
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well i found the derivative to be 10x^4 +30x^2+15 but when i graphed it i couldt figure out where it crossed the x axis
 
ryan.1015 said:
well i found the derivative to be 10x^4 +30x^2+15 but when i graphed it i couldt figure out where it crossed the x axis

Here's what you showed in your first post:
g(x)=2x^5-10x^3=15x-3.

What's with that '=' right after the x^3 term? Did you mean that to be a '+'?

Assuming that's the case, g(x) = 2x^5 - 10x^3 + 15x -3
Your calculation for the derivative -- g'(x) is its name -- is incorrect.
 
I think from equating first derivative to zero u can easily find the point where no change occurs and beyond that it go on changing. and from 2nd derivative u can find the inflection points. Am I correct?
 
ElectroPhysics said:
I think from equating first derivative to zero u can easily find the point where no change occurs and beyond that it go on changing. and from 2nd derivative u can find the inflection points. Am I correct?

Equating the derivative to zero gives you the values where the tangent lines are horizontal, which can help you find local maxima and minima.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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