Finding magnitude and direction of net torque on a dipole

AI Thread Summary
To find the net torque on a dipole with charges of ±3.0 microcoulombs separated by 3.20 nm in an electric field of 8000 N/C, the force is calculated as F = 2.4E-2 N. The effective lever arm is determined using l = 1.84E-9 m. The net torque is then computed using the formula T = qEl, leading to the conclusion that the torque acts in a specific direction, either clockwise or counterclockwise. The calculations confirm the relationship between force, lever arm, and torque in this context. The final answer provides the magnitude and direction of the net torque on the dipole.
ick84
Messages
2
Reaction score
0

Homework Statement



For the dipole shown, the charges are ± 3.0 micro coulombs separated by a distance of 3.20 nm and oriented so that the theta is 35.0 degrees. If the electric field has a magnitude of 8000 N/C, find the magnitude and direction (clockwise/counterclockwise) of the net torque on the dipole about the same axis as before.


Homework Equations



F = qE
torque = Fl

The Attempt at a Solution



first i solved for F = (3.0E-6 C)(8000N/C) = 2.4E-2 N

then solved for l = (3.20nm)(sin35) = 1.84E-9

net torque = 2 * F * l ??
 

Attachments

  • 1027679.jpg
    1027679.jpg
    7.1 KB · Views: 679
Physics news on Phys.org
NVM i solved it...

T = Fl
T = qEl
 
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top