Finding mass in a quanity of heat problem

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In a heat treatment problem, a copper part cools from 400°C to 30°C, losing 80 kcal of heat. The relevant equation used is Q=mcΔT, where m is mass, c is specific heat, and ΔT is the temperature change. The attempted solution rearranges the formula to m=Q/(cΔT) and substitutes values for specific heat and temperature change. There is uncertainty about the correctness of the calculation, indicating a need for clarification on the setup and execution of the formula. Proper application of the formula is essential for determining the mass accurately.
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Homework Statement



In a heat treatment, a hot copper part is quenched with water, cooling it from 400 degrees Celsius to 30 degrees Celsius. What was the mass of the part if it loses 80 kcal of heat.


Homework Equations



Q=mcΔT

The Attempt at a Solution



m=c ΔT/Q m=(0.093cal/g*C°)(370 C° )/ 80Kcal


I gave this a shot but I don't feel like it's right. Any help and hints or even just setting up the formula is appreciated big time. I have a feeling this one is kind of obvious I'm just not seeing it.
 
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Damien20 said:

Homework Statement



In a heat treatment, a hot copper part is quenched with water, cooling it from 400 degrees Celsius to 30 degrees Celsius. What was the mass of the part if it loses 80 kcal of heat.


Homework Equations



Q=mcΔT

The Attempt at a Solution



m=c ΔT/Q m=(0.093cal/g*C°)(370 C° )/ 80Kcal

m = Q/cΔT
 
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