Finding Mass of a Sphere

  • Thread starter Thread starter Ripcurl
  • Start date Start date
  • Tags Tags
    Mass Sphere
AI Thread Summary
To find the mass of a sphere with a radius of 5.3 cm and a density of 8.15 g/cm³, the volume is calculated using the formula for the volume of a sphere, resulting in approximately 623.61 cm³. Multiplying this volume by the density gives a mass of about 5082.46 g. Initial calculations led to confusion, but the correct approach confirms the mass. The key takeaway is to use the given units without unnecessary conversions. The formula for mass remains consistent: Mass = density times volume.
Ripcurl
Messages
19
Reaction score
0

Homework Statement


A sphere of metal has a radius of 5.3 cm and a density of 8.15 g/cm3. What is the mass of the sphere? Answer in units of g.

Homework Equations


Density=mass/volume

Volume of a sphere=4/3лr^3

The Attempt at a Solution


I found the volume by multiplying 4/3 by л and 5.3 squared. I got 66.1850323. I plugged this into the formula for density, manipulated it to get mass by itself and got 539.4118513. This answer seems really unreasonable. I think I need to do some conversions but I'm not sure what to convert. I think I need to convert the radius to meters but the density is in grams/cm cubed and I need to answer in units of grams.
 
Last edited:
Physics news on Phys.org
Mass = density times volume

First, volume of a sphere is 4/3\pir^3.

Next, don't convert anything you've been given the right units for what you've been asked for. Produce a volume for the sphere in terms of cm^3, then

cm^3 * \frac{g.}{cm^3} = g.
 
Last edited by a moderator:
So you're saying find the volume. I got 623.6145193 cm^3. Then I multiply that by the density (8.15) to get the mass. I get 5082.458333. That doesn't seem right. XD
 
But it is. Wow. You're amazing! Thanks! XD
 
Glad to help.

Remember that the equation of finding the mass of a sphere is

Mass = density times volume
 
Last edited by a moderator:
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top