Minimum Force for Moving a Sled on a Horizontal Surface

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To determine the minimum force required to keep a sled moving on a horizontal surface with a kinetic friction coefficient of 0.20 and a mass of 2 slugs, the frictional force is calculated using the formula fs = μs(N), where N is the normal force. The normal force for a sled on a flat surface is equal to the weight, which can be calculated as mass times gravity (2 slugs x 32 ft/s²). This results in a frictional force of 12.8 pounds. The discussion also clarifies that the unit of force is in pounds when using slugs. Understanding these calculations is essential for solving similar physics problems.
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Homework Statement


A sled is pulled over a horizontal surface where the kinetic coefficient of friction is .20. What is the minimum force necessary to keep the sled moving if its mass is 2 slugs?


Homework Equations


fs = Ns(mg)


The Attempt at a Solution


fs = (.20) (2 slugs) (32)
=12.8

This problem has got me stumped. Please help! Thank You.
 
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What is the unit of fs?
 
I assume 12.8 N
 
tutojean said:
I assume 12.8 N
Unit force is N if mass is in kg.
 

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