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Finding pressure of argon gas

  1. Dec 11, 2008 #1
    1. The problem statement, all variables and given/known data
    0.54 mol of argon gas is admitted to an evacuated 90 cm3 container at 10 o C. The gas then undergoes an isochoric heating to a temperature of 400 oC.

    What is the final pressure of the gas (in kPa)?

    2. Relevant equations
    PV = nRT

    3. The attempt at a solution
    P(9.0x10-5 m3) = (.54 mol)(8.314 m3Pa/K mol)(673 K)
    P = 33,571,932 Pa = 33,571.932 kPa

    This number just seems way too large to me, which is why I'm questioning it. Thanks for any help you can provide!
  2. jcsd
  3. Dec 12, 2008 #2


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    Science Advisor
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    Convert it to atmospheres or psi if you want....
  4. Dec 12, 2008 #3


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    Staff: Mentor

    That's a correct answer. 90 mL for half a mole of gas is a pretty small volume even at room temperature (remember at STP it should occupy about 12L).
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